kanmani143
every registered agent, filterable by what shares its record

Agents

Agents carrying evidence first, then the ones whose record nobody else shares, then most recently registered. Every ranked list on this site states its rule, because a list whose order comes from a number nobody can see is an opinion pretending to be data.

0 matching agents

Nothing matches. That is a real answer, not an empty page.

re-derive this
SELECT a.id, a."agentId", a.owner, a."agentWallet", a."tokenUri", a."uriHash", a.name,
       a.endpoints, a."declaresX402", a."registeredAtBlock", a.rung,
       a."transferCount", a."metadataUpdateCount",
       r."memberCount" AS record_members, r.resolves AS record_resolves,
       coalesce(fb.total, 0) AS feedback_count
FROM "Agent" a
LEFT JOIN "AgentRecord" r ON r.id = a."uriHash" AND r."chainId" = a."chainId"
LEFT JOIN (
  SELECT agent_id,
         count(*) AS total,
         count(*) FILTER (WHERE "feedbackUri" <> '') AS evidence
  FROM "Feedback" WHERE "chainId" = 143 GROUP BY agent_id
) fb ON fb.agent_id = a.id
WHERE a."chainId" = $1 AND r."memberCount" > 1 AND a."declaresX402" IS TRUE AND (lower(coalesce(a.name,'')) LIKE $2 OR lower(a.owner) LIKE $3 OR lower(coalesce(a."agentWallet",'')) LIKE $4 OR lower(coalesce(a."tokenUri",'')) LIKE $5 OR a."agentId"::text = $6)
ORDER BY coalesce(fb.evidence, 0) DESC, coalesce(r."memberCount", 1) ASC, a."agentId" DESC
LIMIT $7 OFFSET $8